x^2-0.6x-1.2=0

Solution for x^2-0.6x-1.2=0 equation:

x^2-0.6x-1.2=0

a = 1; b = -0.6; c = -1.2;
Δ = b2-4ac
Δ = -0.62-4·1·(-1.2)
Δ = 5.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{5.16}}{2*1}=\frac{0.6-\sqrt{5.16}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{5.16}}{2*1}=\frac{0.6+\sqrt{5.16}}{2}
$